C语言判断字符串是否回文三种方法实例

#include<stdio.h>
#include<string.h>
int main()
{
	char s[100] ;
	gets(s);
	int start = 0, end = strlen(s) - 1;
	int flag = 1;
	while (start <= end && 1 == flag)
	{
		flag = (s[start] == s[end]);
		start++;
		end--;
	}
	if (1 == flag)
         printf("%s是回文",s);
	else 
         printf("%s不是回文",s);
	return 0;
}

#include<stdio.h>
#include<string.h>
int main()
{
	char s[100] ;
	gets(s);
	int start = 0, end = strlen(s) - 1;
	int flag = 1;
	while (start <= end && 1 == flag)
	{
		flag = (s[start++] == s[end--]);
	}
	1 == flag ? printf("%s是回文", s) : printf("%s不是回文", s);
	return 0;
}

#include<stdio.h>
#include<string.h>
int main()
{
	char s[100] ;
	gets(s);
	int start = 0, end = strlen(s) - 1;
	int flag = 1;
	while (start <= end && flag == (s[start++] == s[end--]));
	
	1 == flag ? printf("%s是回文", s) : printf("%s不是回文", s);
	return 0;
}